Another possibility is that [N-fQ] could be interpreted as a combination of [N-fR] and [N-fB]. I think of 'outward' in continuations as excluding any crossing of a queen's path from the starting square.
Pretty much exactly what I've been getting at. (If Q=BR, then [N-fQ] = [N-fB][N-fR].)
Pretty much exactly what I've been getting at. (If Q=BR, then [N-fQ] = [N-fB][N-fR].)