🕸Fergus Duniho wrote on Fri, Jun 23, 2017 08:44 PM UTC:
So long as there are more participants than games, this method will create unique pairings, so that no one ever plays anyone else more than once, and so long as the difference between players and games isn't too great, it will assure that players who don't play against each other will still play against several of the same opponents. If you hope for everyone to play everyone, then you will need to add more games. But if you are content with everyone playing only nine games, then this method will allow you to distribute players for every game, no matter whether there is an odd or an even number of participants.
So long as there are more participants than games, this method will create unique pairings, so that no one ever plays anyone else more than once, and so long as the difference between players and games isn't too great, it will assure that players who don't play against each other will still play against several of the same opponents. If you hope for everyone to play everyone, then you will need to add more games. But if you are content with everyone playing only nine games, then this method will allow you to distribute players for every game, no matter whether there is an odd or an even number of participants.