George Duke wrote on Mon, Jun 25, 2007 08:56 PM UTC:
Puzzle One Solution:
8 P____K____N____ ____ ____B____ ____P White small letters
7 P____ ____ ____ ____ ____C____ ____P Conventional Pawns
6 P____D____E____ ____ ____R____ ____P D = Dragon 5-square,5+way
5 P____I____ ____ ____ ____ ____ ____P C = Crooked Bishop
4 p____i____ ____w____w____ ____ ____p B = Ibis leaper
3 p____ ____ ____w____ ____ ____ ____p E = Elbow Chess Rook
2 p____ ____ ____ ____ ____f____w____p w = Wazir (1,2)
1 p____ ____ ____ ____f____k____ ____p f = Ferz (2,2)
I,i = Immobilizer
a b c d e f g h
There would be thousands of hard-to-find solutions CVPage-indexed pieces. One explanation: put all 16 standard Pawns in a-file and h-file. How about Immobilizers (Ultima) at b4 White and b5 Black. Black Dragon at b6 is after 'Falcons, Scorpions and Dragon.' E is Elbow Chess Rook in 'Multipath Chess Pieces,' after Pritchard ECV, having to make one 90-degree change of direction each move. Black Crooked Bishop at f7 is Betza's. Black Ibis(or Namel: 2,8) at f8 is Gilman concoction (hey let's find the things some use).
Justification: If Wazir at either d4 or d3 moves, Dragon-b6 has a pathway.
If Wazir-e4 moves or Wazir-g2 moves, Crooked Bishop at f7 has pathway.
If Ferz-f2 moves, Rook checks making it illegal.
If Ferz-e1 moves, Elbow-Rook-c6 has its pathway.
King cannot move because of Ibis-f8 and the Elbow Chess one again.
So, no White piece can move: beyond 'zugzwang,' half-the-board immobilization by all pre-existent pieces. QED. (More elegant may be upgrading one+ W/F to at least N because of relative strengths or some one-piece-type principle of economy. Puzzle Two remains more difficult)
Puzzle One Solution: 8 P____K____N____ ____ ____B____ ____P White small letters 7 P____ ____ ____ ____ ____C____ ____P Conventional Pawns 6 P____D____E____ ____ ____R____ ____P D = Dragon 5-square,5+way 5 P____I____ ____ ____ ____ ____ ____P C = Crooked Bishop 4 p____i____ ____w____w____ ____ ____p B = Ibis leaper 3 p____ ____ ____w____ ____ ____ ____p E = Elbow Chess Rook 2 p____ ____ ____ ____ ____f____w____p w = Wazir (1,2) 1 p____ ____ ____ ____f____k____ ____p f = Ferz (2,2) I,i = Immobilizer a b c d e f g h There would be thousands of hard-to-find solutions CVPage-indexed pieces. One explanation: put all 16 standard Pawns in a-file and h-file. How about Immobilizers (Ultima) at b4 White and b5 Black. Black Dragon at b6 is after 'Falcons, Scorpions and Dragon.' E is Elbow Chess Rook in 'Multipath Chess Pieces,' after Pritchard ECV, having to make one 90-degree change of direction each move. Black Crooked Bishop at f7 is Betza's. Black Ibis(or Namel: 2,8) at f8 is Gilman concoction (hey let's find the things some use). Justification: If Wazir at either d4 or d3 moves, Dragon-b6 has a pathway. If Wazir-e4 moves or Wazir-g2 moves, Crooked Bishop at f7 has pathway. If Ferz-f2 moves, Rook checks making it illegal. If Ferz-e1 moves, Elbow-Rook-c6 has its pathway. King cannot move because of Ibis-f8 and the Elbow Chess one again. So, no White piece can move: beyond 'zugzwang,' half-the-board immobilization by all pre-existent pieces. QED. (More elegant may be upgrading one+ W/F to at least N because of relative strengths or some one-piece-type principle of economy. Puzzle Two remains more difficult)